document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=495923>Question 495923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two cars leave from the same location and go in opposite directions. The north bound car travels 15mph slower than the south bound car. After 6 hours they are 630 miles apart. Find the rate of each car. \r<BR>\n" );
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document.write( "How would i set this equation up to find the value of (X) if (X) is the rate of the cars </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336265 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336265\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Distance(d) equals Rate(r) times Time(t) or d=rt;  r=d/t and t=d/r\r<BR>\n" );
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document.write( "Now you need to think about this a little.  The cars are traveling at different rates, so X can't be the \"rate of the cars\".  But X can be the rate of one of the cars:\r<BR>\n" );
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document.write( "Let X=rate of north-bound car<BR>\n" );
document.write( "Then X+15=rate of south-bound car\r<BR>\n" );
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document.write( "Distance north-bound car travels after 6 hours=X*6<BR>\n" );
document.write( "Distance south-bound car travels after 6 hours=(x+15)*6<BR>\n" );
document.write( "Now we are told that these two distances add up to 630 mi, soooo<BR>\n" );
document.write( "6X+6(X+15)=630 get rid of parens<BR>\n" );
document.write( "6X+6X+90=630  subtract 90 from each side<BR>\n" );
document.write( "12X=540<BR>\n" );
document.write( "X=45 mph---------------------------rate of north-bound car<BR>\n" );
document.write( "X+15=45+15=60 mph----------------------rate of south-bound car\r<BR>\n" );
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document.write( "CK<BR>\n" );
document.write( "45*6+60*6=630<BR>\n" );
document.write( "270+360=630<BR>\n" );
document.write( "630=630\r<BR>\n" );
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document.write( "Another way:\r<BR>\n" );
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document.write( "We know the cars are separating at the rate of X+X+15mph=2X+15 mph<BR>\n" );
document.write( "in 6 hours they have traveled (2X+15)*6=12X+90 miles and we are told that this equals 630 mi, sooo<BR>\n" );
document.write( "12X+90=630----same as before\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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