document.write( "Question 495929: please help with method of solution for n/2-1/3=13/6 \n" ); document.write( "
Algebra.Com's Answer #336262 by ptaylor(2198) You can put this solution on YOUR website! (n/2)-1/3=13/6 First, lets get rid of the fractions. We do this by multiplying each term in the equation by the lowest common denominator which is 6, sooo \n" ); document.write( "6*(n/2)-6*(1/3)=6*(13/6) and this gives us \n" ); document.write( "3n-2=13 add 2 to each side \n" ); document.write( "3n-2+2=13+2 collect like terms \n" ); document.write( "3n=15 divide each side by 3 \n" ); document.write( "n=5 \n" ); document.write( "CK \n" ); document.write( "(5/2)-1/3=13/6 we could multiply by the lowest common denominator again or we could just add the fractions. Lets add the fractions: \n" ); document.write( "5/2=15/6 (multiply numerator and denominator by 3) \n" ); document.write( "1/3=2/6 (multiply numerator and denominator by 2), sooooo \n" ); document.write( "15/6-2/6=13/6 \n" ); document.write( "13/6=13/6\r \n" ); document.write( "\n" ); document.write( "Note that I used parens for some of the fractions (eg (n/2)) just to make sure there is no confusion. \n" ); document.write( "n/2-1/3 could be read as n/(2-1/3) or (n/2)-1/3 \n" ); document.write( "Parens helps to underscore that some expressions are one quantity.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor \n" ); document.write( " \n" ); document.write( " |