document.write( "Question 495929: please help with method of solution for n/2-1/3=13/6 \n" ); document.write( "
Algebra.Com's Answer #336262 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
(n/2)-1/3=13/6 First, lets get rid of the fractions. We do this by multiplying each term in the equation by the lowest common denominator which is 6, sooo
\n" ); document.write( "6*(n/2)-6*(1/3)=6*(13/6) and this gives us
\n" ); document.write( "3n-2=13 add 2 to each side
\n" ); document.write( "3n-2+2=13+2 collect like terms
\n" ); document.write( "3n=15 divide each side by 3
\n" ); document.write( "n=5
\n" ); document.write( "CK
\n" ); document.write( "(5/2)-1/3=13/6 we could multiply by the lowest common denominator again or we could just add the fractions. Lets add the fractions:
\n" ); document.write( "5/2=15/6 (multiply numerator and denominator by 3)
\n" ); document.write( "1/3=2/6 (multiply numerator and denominator by 2), sooooo
\n" ); document.write( "15/6-2/6=13/6
\n" ); document.write( "13/6=13/6\r
\n" ); document.write( "\n" ); document.write( "Note that I used parens for some of the fractions (eg (n/2)) just to make sure there is no confusion.
\n" ); document.write( "n/2-1/3 could be read as n/(2-1/3) or (n/2)-1/3
\n" ); document.write( "Parens helps to underscore that some expressions are one quantity.\r
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\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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