document.write( "Question 495854: The measure of the complement of an angle times seven is equivalent to three times the supplement. Find the complement.\r
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\n" ); document.write( "90-7x = 3x
\n" ); document.write( "90 = 10x
\n" ); document.write( "9 = x\r
\n" ); document.write( "\n" ); document.write( "90-63 = 27
\n" ); document.write( "The complement is 27 degrees?
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Algebra.Com's Answer #336260 by bucky(2189)\"\" \"About 
You can put this solution on YOUR website!
Let's work with the angle itself. Let x be the unknown angle.
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\n" ); document.write( "If x is the unknown angle, then its complement is 90 - x and its supplement is 180 - x.
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\n" ); document.write( "The problem then tells you that 7 times the complement equals 3 times the supplement. In equation form this is:
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\n" ); document.write( "7*(90 - x) = 3*(180 - x)
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\n" ); document.write( "Multiply out the two sides:
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\n" ); document.write( "630 - 7x = 540 - 3x
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\n" ); document.write( "Subtract 540 from both sides:
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\n" ); document.write( "90 - 7x = - 3x
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\n" ); document.write( "Add 7x to both sides:
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\n" ); document.write( "90 = 4x
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\n" ); document.write( "Solve for the unknown angle by dividing both sides by 4 to get:
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\n" ); document.write( "22.5 = x
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\n" ); document.write( "So the unknown angle is 22.5 degrees. Then its complement is 90 - 22.5 and that is 67.5 degrees.
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\n" ); document.write( "Its supplement is 180 - 22.5 and it equals 157.5 degrees.
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\n" ); document.write( "To check our answers, let's return to the original problem which states that 7 times the complement equals 3 times the supplement. In equation form this is:
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\n" ); document.write( "7*67.5 = 3*157.5
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\n" ); document.write( "and doing the multiplications shown on both sides results in:
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\n" ); document.write( "472.5 = 472.5
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\n" ); document.write( "Since both sides are equal, we know that the answer is correct. The complement that you were to find is 67.5 degrees.
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\n" ); document.write( "Hope this helps you to understand this problem a little better. This problem is made difficult by how it's written. Once you get the wording correctly interpreted into equation form, getting the solution is actually the easier part.
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