document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=495631>Question 495631</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From a group of 12 people I am to form 4 teams of 3 players each. In how many ways can this be done. (This is closely related to the previous problem, but note that the teams are not ordered.\r<BR>\n" );
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document.write( "I tried doing (12x11x10x9)/(3x2x1)<BR>\n" );
document.write( "and<BR>\n" );
document.write( "12!/4!3!<BR>\n" );
document.write( "but both are wrong </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336212 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> From a group of 12 people I am to form 4 teams of 3 players each. In how many ways can this be done.<BR>\n" );
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document.write( "# of ways to form the 1st team of 3: 12C3 = (12*11*10)/(1*2*3) = 220 ways<BR>\n" );
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document.write( "# of ways to form the 2nd team: 9C3 = (9*8*7)/(1*2*3) = 84 ways<BR>\n" );
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document.write( "# of ways to form the 3rd team: 6C3 = (6*5*4)/(1*2*3) = 20 ways<BR>\n" );
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document.write( "# of ways to form the 4th team: 3C3 = 1 way<BR>\n" );
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document.write( "Total # of ways: 220*84*20*1 = 369,600<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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