document.write( "Question 495789: how much pure acid should be mixed with 4 gallons of 50% acid solution in order to get 60% acid solution? \n" ); document.write( "

Algebra.Com's Answer #336193 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"x\"$ = gallons of pure acid to be added
\n" ); document.write( "given:
\n" ); document.write( " $\"+.5%2A4+=+2+\"$ gallons of acid in 50% solution
\n" ); document.write( "-----------
\n" ); document.write( " $\"+%28x+%2B+2%29+%2F+%28+x+%2B+4+%29+=+.6+\"$
\n" ); document.write( " $\"+x+%2B+2+=+.6%2A%28+x+%2B+4+%29+\"$
\n" ); document.write( " $\"+x+%2B+2+=+.6x+%2B+2.4+\"$
\n" ); document.write( " $\"+.4x+=+.4+\"$
\n" ); document.write( " $\"+x+=+1+\"$
\n" ); document.write( "1 gallon of pure acid needs to be added
\n" ); document.write( "check:
\n" ); document.write( " $\"+%28x+%2B+2%29+%2F+%28+x+%2B+4+%29+=+.6+\"$
\n" ); document.write( " $\"+%281+%2B+2%29+%2F+%28+1+%2B+4+%29+=+.6+\"$
\n" ); document.write( " $\"+3%2F5+=+.6+\"$
\n" ); document.write( " $\"+3+=+3+\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );