document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=495558>Question 495558</A>: <I><SPAN STYLE=\"word-break: break-all;\"> KM bisects <JKL, m<JKM= (4x+6)degrees, and m<MKL= (7x-12) degrees. Find m<JKM. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336182 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336182\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two angles are equal so we can solve for x.<BR>\n" );
document.write( "4x + 6 = 7x - 12<BR>\n" );
document.write( "18 = 3x<BR>\n" );
document.write( "6 = x<BR>\n" );
document.write( "4(6) + 6 = 30 degrees = angle JKM<BR>\n" );
document.write( "7(6) - 12 = 30 degrees =angle MKL<BR>\n" );
document.write( "Cleomenius\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );