document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=495607>Question 495607</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to find the x and y of the following linear equation systems\r<BR>\n" );
document.write( "\n" );
document.write( "2x + Y = -6<BR>\n" );
document.write( "3x + Y = -10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336122 by </B><A HREF=/tutors/aboutme.mpl?userid=IFY><B>IFY(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IFY><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=IFY><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336122\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
document.write( "  2x + y = -6 ----- equation 1<BR>\n" );
document.write( "  3x + y = -10 ----equation 2\r<BR>\n" );
document.write( "\n" );
document.write( "first of all subtract equation 1 from equation 2\r<BR>\n" );
document.write( "\n" );
document.write( "  (2x - 3x)+ (y -y) = (-6 - -10)\r<BR>\n" );
document.write( "\n" );
document.write( "     -x + 0 = 4\r<BR>\n" );
document.write( "\n" );
document.write( "      -x = 4\r<BR>\n" );
document.write( "\n" );
document.write( "      x = -4\r<BR>\n" );
document.write( "\n" );
document.write( " substitute x = -4 into equation 1\r<BR>\n" );
document.write( "\n" );
document.write( "     2x + y = -6\r<BR>\n" );
document.write( "\n" );
document.write( "     2(-4)+ y = -6\r<BR>\n" );
document.write( "\n" );
document.write( "     -8 + y = -6\r<BR>\n" );
document.write( "\n" );
document.write( "      y = -6 + 8\r<BR>\n" );
document.write( "\n" );
document.write( "      y = 2\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "    { x = -4 , y = 2 }  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );