document.write( "Question 495401: evaluate by simplifying \r
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document.write( "23×8-1\r
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Algebra.Com's Answer #336086 by Edwin McCravy(20056)![]() ![]() You can put this solution on YOUR website! \r\n" ); document.write( "23×8-1\r\n" ); document.write( "\r\n" ); document.write( "23 means 2×2×2 which is 8. So now we have:\r\n" ); document.write( "\r\n" ); document.write( " 8×8-1\r\n" ); document.write( "\r\n" ); document.write( "and since 8 is the same as 81, we now have:\r\n" ); document.write( "\r\n" ); document.write( " 81×8-1\r\n" ); document.write( "\r\n" ); document.write( "Now add the exponents of 8 and get\r\n" ); document.write( "\r\n" ); document.write( " 80\r\n" ); document.write( "\r\n" ); document.write( "Any positive or negative number to the zero power is 1\r\n" ); document.write( "\r\n" ); document.write( "Answer: 1\r\n" ); document.write( "\r\n" ); document.write( "------------------------\r\n" ); document.write( "\r\n" ); document.write( "You can also do it by using the definition of negative exponents:\r\n" ); document.write( "\r\n" ); document.write( "23×8-1\r\n" ); document.write( "\r\n" ); document.write( "23×\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |