document.write( "Question 495346: Soybean meal is 16% protein, cornmeal is 8% protein. How many pounds of each should be mixed together in order to get 320-lb mixture that is 11% protein? \n" ); document.write( "
Algebra.Com's Answer #336069 by ptaylor(2198)\"\" \"About 
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Let x=amount of soybean meal needed
\n" ); document.write( "Then 320-x=amount of cornmeal needed\r
\n" ); document.write( "\n" ); document.write( "Now we know that the amount of pure protein that exists before the mixture takes place has to equal the amount of pure protein that exists after the mixture takes place, sooooo:
\n" ); document.write( "0.16x+0.08(320-x)=0.11*320
\n" ); document.write( "0.16x+25.6-0.08x=35.2 subtract 25.6 from each side
\n" ); document.write( "0.08x=9.6
\n" ); document.write( "x=120 pounds----amount of soybean meal needed
\n" ); document.write( "320-120=200 pounds--amount of cornmeal needed\r
\n" ); document.write( "\n" ); document.write( "CK
\n" ); document.write( "0.16*120+0.08*200=35.2
\n" ); document.write( "19.2+16=35.2
\n" ); document.write( "35.2=35.2\r
\n" ); document.write( "\n" ); document.write( "Hope this helps----ptaylor
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