document.write( "Question 495316: a person travels a total of 35 minutes. They jog to a location at 5 meters per second and walk back at 2 meters per second. How many total meters did they travel? \n" ); document.write( "
Algebra.Com's Answer #336065 by ptaylor(2198)\"\" \"About 
You can put this solution on YOUR website!
Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r
\n" ); document.write( "\n" ); document.write( "Ok, lets deal in minutes:
\n" ); document.write( "5 meters/sec=5*60 =300 meters/min
\n" ); document.write( "2 meters/sec=2*60=120 meters/min
\n" ); document.write( "Let d=one-way distance
\n" ); document.write( "t1=time required jogging out
\n" ); document.write( "t2=time required walking back
\n" ); document.write( "t1+t2=35
\n" ); document.write( "t1=d/300
\n" ); document.write( "t2=d/120
\n" ); document.write( "d/300+d/120=35 multiply each term by 600
\n" ); document.write( "2d+5d=21000
\n" ); document.write( "7d=21000
\n" ); document.write( "d=3000 meters
\n" ); document.write( "2d=6000 meters total meters travelled\r
\n" ); document.write( "\n" ); document.write( "Hope this helps--ptaylor
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