document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=495248>Question 495248</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find the value of k so that the equation 5x^2-8x+k=0 will have roots whose product is equal to 2/3?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #336027 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=336027\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  find the value of k so that the equation 5x^2-8x+k=0 will have roots whose product is equal to 2/3?\r<BR>\n" );
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document.write( "Roots are [8 +- sqrt(64 - 4*5*k)]/10<BR>\n" );
document.write( "x = (4/5)+sqrt(64-20k)/10 and x = (4/5)-sqrt(64-20k)]/10<BR>\n" );
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document.write( "Their product = (4/5)^2 - [(64-20k)/10]<BR>\n" );
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document.write( "Solve for \"k\":<BR>\n" );
document.write( "(4/5)^2 - [(64-20k)/10]  = 2/3<BR>\n" );
document.write( "(16/25) - 6.4 + 2k = 2/3<BR>\n" );
document.write( "0.64-6.4+2k = 2/3<BR>\n" );
document.write( "2k -5.76 = 2/3<BR>\n" );
document.write( "k - 2.88 = 1/3<BR>\n" );
document.write( "k = 3.2133<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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