document.write( "Question 495150: How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid? \n" ); document.write( "
Algebra.Com's Answer #335990 by stanbon(75887)\"\" \"About 
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How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid?
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\n" ); document.write( "Equation:
\n" ); document.write( "water + water = water
\n" ); document.write( "0.20*40 + x = 0.80(40+x)
\n" ); document.write( "Multiply thru by 100 to get:
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\n" ); document.write( "20*40 + 100x = 80*40 + 80x
\n" ); document.write( "20x = 60*40
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\n" ); document.write( "x = 120 L (amt. of water to be added)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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