document.write( "Question 495150: How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid? \n" ); document.write( "
Algebra.Com's Answer #335990 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! How much water must you add to a 40 L 80% acid solution to reduce it to 20% acid? \n" ); document.write( "---------------- \n" ); document.write( "Equation: \n" ); document.write( "water + water = water \n" ); document.write( "0.20*40 + x = 0.80(40+x) \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "------ \n" ); document.write( "20*40 + 100x = 80*40 + 80x \n" ); document.write( "20x = 60*40 \n" ); document.write( "--- \n" ); document.write( "x = 120 L (amt. of water to be added) \n" ); document.write( "===================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============ \n" ); document.write( " |