document.write( "Question 50517: I have a question that is the population is given by P=10,000(1.04)^t where t is number of years after 1988. I have to find the population in 1988 and 1989.
\n" ); document.write( "In 1988 I have P=10,000 (1.04)^0 which is 10,000 people
\n" ); document.write( "in 1989 I have P=10,000(1.04)^1 which came to 10,400 people.
\n" ); document.write( "Am I on hte right track with this sort of problem???
\n" ); document.write( "Thanks for the help! \n" ); document.write( "

Algebra.Com's Answer #33599 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
Yes. Right on track.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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