document.write( "Question 495115: 2. Determine whether the relation {(–2, 3), (–5, 6), (3, 0), (1, 1)} is a function\r
\n" ); document.write( "\n" ); document.write( "3. Delete one ordered pair so that the relation {(–4, 2), (1, 6), (0, 0), (–4, 6)} is a function.\r
\n" ); document.write( "\n" ); document.write( "Find ƒ(–5) for each function.
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Algebra.Com's Answer #335967 by Edwin McCravy(20056)\"\" \"About 
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2. Determine whether the relation {(–2, 3), (–5, 6), (3, 0), (1, 1)} is a function
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document.write( "We look at the first coordinates -2, -5, 3, and 1. None of those are\r\n" );
document.write( "the same, so it is function.\r\n" );
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\n" ); document.write( "3. Delete one ordered pair so that the relation {(–4, 2), (1, 6), (0, 0), (–4, 6)} is a function.
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document.write( "We look at the first coordinates -4, 1, 0, and -4. Two of those are\r\n" );
document.write( "the same -4, so it is NOT a function.  To make it into a function we can\r\n" );
document.write( "delete either (-4, 2) or (-4, 6).  You can put either of these as the\r\n" );
document.write( "solution:\r\n" );
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document.write( "{(1, 6), (0, 0), (–4, 6)} or {(–4, 2), (1, 6), (0, 0)}\r\n" );
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\n" ); document.write( "Find ƒ(–5) for each function.\r
\n" ); document.write( "\n" ); document.write( "5. ƒ(x) = 5x + 35
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document.write( "Everywhere you see an x, replace it by (-5)\r\n" );
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document.write( "     ƒ(-5) = 5(-5) + 35\r\n" );
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document.write( "Then simplify the right side:\r\n" );
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document.write( "     ƒ(-5) = -25 + 35\r\n" );
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document.write( "     ƒ(-5) = 10\r\n" );
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\n" ); document.write( "6. ƒ(x) = x² – x
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document.write( "Everywhere you see an x, replace it by (-5)\r\n" );
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document.write( "     ƒ(-5) = (-5)² - (-5)\r\n" );
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document.write( "Then simplify the right side:\r\n" );
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document.write( "     ƒ(-5) = 25 + 5\r\n" );
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document.write( "     ƒ(-5) = 30\r\n" );
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document.write( "Edwin

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