document.write( "Question 494816: The area of a square is (16x^2 + 40x +25cm^2) what is x if the perimeter of the square is 52cm? \n" ); document.write( "

Algebra.Com's Answer #335949 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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The area of a square is (16x^2 + 40x +25cm^2) what is x if the perimeter of the square is 52cm?
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\n" ); document.write( "P = 52
\n" ); document.write( "therefore one side of the square (s)
\n" ); document.write( "s = 52/4
\n" ); document.write( "s = 13 cm
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\n" ); document.write( "A = s^2
\n" ); document.write( "therefore
\n" ); document.write( "A = 13^2
\n" ); document.write( "A = 169 sq/cm
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\n" ); document.write( "So we have:
\n" ); document.write( "16x^2 + 40x + 25 = 169
\n" ); document.write( "16x^2 + 40x + 25 - 169 = 0
\n" ); document.write( "16x^2 + 40x - 144 = 0
\n" ); document.write( "Simplify, divide by 8
\n" ); document.write( "2x^2 + 5x - 18 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(2x+9)(x-2) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "x = 2
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\n" ); document.write( "See if that checks out, replace x with 2 in the given expression
\n" ); document.write( "16(2^2) + 40(2) + 25
\n" ); document.write( "64 + 80 + 25 = 169 \n" ); document.write( "

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