document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493684>Question 493684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 30 inches, and its area is 54 square inches.  Find the length of the longest side of the rectangle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335876 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335876\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2L + 2W = 30<BR>\n" );
document.write( "L*W = 54<BR>\n" );
document.write( "L = 54/w<BR>\n" );
document.write( "Now, we substitute the L into the first equation.<BR>\n" );
document.write( "108/w  + 2W  = 30<BR>\n" );
document.write( "108 + 2W^2 = 30w<BR>\n" );
document.write( "2w^2 - 30W + 108 = 0<BR>\n" );
document.write( "2(W^2 - 15w + 54)<BR>\n" );
document.write( "2(w - 6)( w - 9)<BR>\n" );
document.write( "Our longest leg is 9, the shortest is 6.<BR>\n" );
document.write( "18 inches + 12 inches = 30 inches.<BR>\n" );
document.write( "9 inches * 6 inches = 54 inches.<BR>\n" );
document.write( "Cleomenius.\r<BR>\n" );
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