document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=494025>Question 494025</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you solve: angle ABD and angle BDE are supplementary. Find the measure of both angles. The problem is... Angle ABD=(3x12), angle BDE=(7x-32) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335857 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I didn't know if the first angle was 3x + 12 or 3x - 12, so I worked it out both ways.\r<BR>\n" );
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document.write( "3x + 12 + 7x - 32 = 180 <BR>\n" );
document.write( "10x - 20 = 180<BR>\n" );
document.write( "10x = 200.<BR>\n" );
document.write( "x = 20<BR>\n" );
document.write( "(20)3 = 60  +  12 = 72<BR>\n" );
document.write( "(20)7 = 140 -  32 = 108<BR>\n" );
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document.write( "3x - 12 + 7x - 32 = 180 <BR>\n" );
document.write( "10x - 44 = 180<BR>\n" );
document.write( "10x  = 224<BR>\n" );
document.write( "x = 22.4<BR>\n" );
document.write( "3(22.4) = 67.2 - 12 = 55.2 <BR>\n" );
document.write( "7(22.4) = 156.8 - 32 = 124.8<BR>\n" );
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document.write( "Cleomenius. </SPAN>\n" );
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