document.write( "Question 494838: Please help me with this problem. I need to solve the equation for solutions over the interval [0 degrees,360 degrees):
\n" ); document.write( "\"+cos%5E2%28x%29=sin%5E2%28x%29%2B1+\"
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Algebra.Com's Answer #335822 by Gogonati(855)\"\" \"About 
You can put this solution on YOUR website!
Substitute in our equation \"%28sinx%29%5E2=1-%28cosx%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"%28cosx%29%5E2=%281-%28cox%29%5E2%29%2B1\" => \"2%28cosx%29%5E2=2\" => \"%28cosx%29%5E2=1\"\r
\n" ); document.write( "\n" ); document.write( "From the final equation we get: cosx=1 and cosx=-1. Solving this two equations we \r
\n" ); document.write( "\n" ); document.write( "get:1) cosx=1 => \"x=2n%2Api\", and 2)cosx=-1 => \"x=%282n-1%29%2Api\", where\r
\n" ); document.write( "\n" ); document.write( "n=0, +-1, +-2, ...
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