document.write( "Question 494763: A loaf of bread is normally distributed with a mean of22 oz. and a standard deviation of 0.5 oz.
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document.write( "a, what is the probability that a loaf is btwn 22.75and 23.00?
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document.write( "B, 5% of the loafs will weigh less than_____ ounces?
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document.write( "C, assuming 200 loaves are baked on a given day, how many of these will weigh more than 23 ounces? thanks for the help... \n" );
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Algebra.Com's Answer #335804 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A loaf of bread is normally distributed with a mean of 22 oz. and a standard deviation of 0.5 oz. \n" ); document.write( "a, what is the probability that a loaf is btwn 22.75 and 23.00? \n" ); document.write( "z(22.75) = (22.75-22)/0.5 = 0.75/0.5 = 1.5 \n" ); document.write( "z(23) = (23-22)/0.5 = 2 \n" ); document.write( "---- \n" ); document.write( "P(22.75 < x < 2300) = P(1.5 < z < 2) = 0.0441 \n" ); document.write( "-------------------------------------------------------------- \n" ); document.write( "B, 5% of the loafs will weigh less than_____ ounces? \n" ); document.write( "Find the z-value with a left tail of 5%: \n" ); document.write( "z = invNorm(0.05) = -1.645 \n" ); document.write( "Find the corresponding x value using x = zs + u \n" ); document.write( "x = -1.645*0.5 + 22 = 21.1775 \n" ); document.write( "----------------------------------------------------- \n" ); document.write( "C, assuming 200 loaves are baked on a given day, how many of these will weigh more than 23 ounces? \n" ); document.write( "z(23) = 2 \n" ); document.write( "P(x > 23) = P(z > 2) = 0.0228 \n" ); document.write( "Expected # above 23 = 0.0228*200 = 4.55 loaves \n" ); document.write( "===================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "=========== \n" ); document.write( " |