document.write( "Question 494801: I'm struggling to calculate this, stats is one of my subjects (long distance learning), but do not understand it. Could you please show me how to calculate the following:\r
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document.write( "A normal population has a mean of 75 and a standard deviation of 5. A sample of size 40 has been randomly selected. The probability that the sample mean is less than 74 is equal to:\r
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document.write( "1. 0.4207
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document.write( "2. 0.0020
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document.write( "3. 0.1038
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document.write( "4. 0.0548
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document.write( "5. 0.5793 \n" );
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Algebra.Com's Answer #335802 by stanbon(75887) ![]() You can put this solution on YOUR website! A normal population has a mean of 75 and a standard deviation of 5. A sample of size 40 has been randomly selected. The probability that the sample mean is less than 74 is equal to: \n" ); document.write( "------------ \n" ); document.write( "t(74) = (74-75)/[5/sqrt(40)] = -1.2649 \n" ); document.write( "--- \n" ); document.write( "P(x-bar < 74) = P(t < -1.2649 when df = 39) = 0.1067 \n" ); document.write( "=========================== \n" ); document.write( "If you use the z-distribution you would get: \n" ); document.write( "P(x-bar < 74) = P(z <-1.2649) = 0.1030 \n" ); document.write( "=========================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================== \n" ); document.write( " \n" ); document.write( "1. 0.4207 \n" ); document.write( "2. 0.0020 \n" ); document.write( "3. 0.1038 \n" ); document.write( "4. 0.0548 \n" ); document.write( "5. 0.5793 \n" ); document.write( " \n" ); document.write( " |