document.write( "Question 494801: I'm struggling to calculate this, stats is one of my subjects (long distance learning), but do not understand it. Could you please show me how to calculate the following:\r
\n" ); document.write( "\n" ); document.write( "A normal population has a mean of 75 and a standard deviation of 5. A sample of size 40 has been randomly selected. The probability that the sample mean is less than 74 is equal to:\r
\n" ); document.write( "\n" ); document.write( "1. 0.4207
\n" ); document.write( "2. 0.0020
\n" ); document.write( "3. 0.1038
\n" ); document.write( "4. 0.0548
\n" ); document.write( "5. 0.5793
\n" ); document.write( "

Algebra.Com's Answer #335802 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
A normal population has a mean of 75 and a standard deviation of 5. A sample of size 40 has been randomly selected. The probability that the sample mean is less than 74 is equal to:
\n" ); document.write( "------------
\n" ); document.write( "t(74) = (74-75)/[5/sqrt(40)] = -1.2649
\n" ); document.write( "---
\n" ); document.write( "P(x-bar < 74) = P(t < -1.2649 when df = 39) = 0.1067
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\n" ); document.write( "If you use the z-distribution you would get:
\n" ); document.write( "P(x-bar < 74) = P(z <-1.2649) = 0.1030
\n" ); document.write( "===========================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "==================
\n" ); document.write( "
\n" ); document.write( "1. 0.4207
\n" ); document.write( "2. 0.0020
\n" ); document.write( "3. 0.1038
\n" ); document.write( "4. 0.0548
\n" ); document.write( "5. 0.5793
\n" ); document.write( "
\n" ); document.write( "
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