document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=494785>Question 494785</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Trains A & B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes the station at 12:20 A.M. If train B passes the station at 12:35 A.M., at what time will train B catch up to train A? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335800 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335800\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Trains A & B are traveling in the same direction on parallel tracks. Train A is traveling at 40 miles per hour and train B is traveling at 48 miles per hour. Train A passes the station at 12:20 A.M. If train B passes the station at 12:35 A.M., at what time will train B catch up to train A?<BR>\n" );
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document.write( "let x=travel time of train A in hrs<BR>\n" );
document.write( "(x-15/60)=(x-1/4)=travel time of train B in hrs<BR>\n" );
document.write( "Both trains must travel the same distance<BR>\n" );
document.write( "Distance=speed*travel time<BR>\n" );
document.write( "40x=48*(x-1/4)=48x-12<BR>\n" );
document.write( "8x=12<BR>\n" );
document.write( "x=1.5 hr<BR>\n" );
document.write( "Ans:<BR>\n" );
document.write( "Train B will catch up to train A in 1.5 hrs at 1:50 A.M. </SPAN>\n" );
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