document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=494527>Question 494527</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Simplify f(x)= 10 ^ log2 + 2logx and find it's value when x= sqrt3. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335793 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335793\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Simplify f(x)= 10 ^ log2 + 2logx and find it's value when x= sqrt3.<BR>\n" );
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document.write( "f(x)= 10 ^ log2 + 2logx<BR>\n" );
document.write( "f(&#8730;3)=10 ^ log2 + 2log(&#8730;3)<BR>\n" );
document.write( "base raised to log of number=number<BR>\n" );
document.write( "f(&#8730;3)=2 + 2log(&#8730;3)=2+log(f(&#8730;3)=2 + log(&#8730;3^2)<BR>\n" );
document.write( "f(&#8730;3)=2+log 3=2.4771 </SPAN>\n" );
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