document.write( "Question 494308: the difference between seven times one number and three times a second number is 25. The sum of twice the first and five times the second is 95. Find the numbers.
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Algebra.Com's Answer #335773 by Maths68(1474)\"\" \"About 
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Let x and y are two numbers
\n" ); document.write( "According to given conditions
\n" ); document.write( "7x-3y=25 ………..(1)
\n" ); document.write( "2x+5y=95……..(2)\r
\n" ); document.write( "\n" ); document.write( "Multiply (1) by 2 and (2) by -7 and add
\n" ); document.write( "14x-6y=50
\n" ); document.write( "-14x-35y=-665
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\n" ); document.write( "-41y=-615\r
\n" ); document.write( "\n" ); document.write( "y=-615/-41
\n" ); document.write( "y=15
\n" ); document.write( "Put the value of y in either equations (1) or (2) to get x
\n" ); document.write( "2x+5y=95……..(2)
\n" ); document.write( "2x+5(15)=95
\n" ); document.write( "2x+75=95
\n" ); document.write( "2x=95-75
\n" ); document.write( "2x=20
\n" ); document.write( "x=20/2
\n" ); document.write( "x=10\r
\n" ); document.write( "\n" ); document.write( "Numbers are 10 and 15\r
\n" ); document.write( "\n" ); document.write( "Check
\n" ); document.write( "Put the value of x and y in either equations (1) or (2)
\n" ); document.write( "7x-3y=25………..(1)
\n" ); document.write( "7(10)-3(15)=25
\n" ); document.write( "70-45=25
\n" ); document.write( "25=25
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