document.write( "Question 494627: I am having a hard time with multiplying out (2+h)^3. I have tried to do
\n" ); document.write( "(2+h)(2+h)(2+h) and did (2^2+2h+h^2)= (4+2h+h^2) . I am using this in Derivatives. \r
\n" ); document.write( "\n" ); document.write( "So If f(x)=x^3 I have to find the tangent line of the equation through point (2,8). \r
\n" ); document.write( "\n" ); document.write( "So F'(2+h)= ((2+h))^3 Which is (4+2h+h^2)
\n" ); document.write( "Then F'(2)= (2)^3 Which is (8)\r
\n" ); document.write( "\n" ); document.write( "So then I take (4+2h+h^2)-(8)\r
\n" ); document.write( "\n" ); document.write( "and I get -4+2h+h^2/h Do you see my problem.\r
\n" ); document.write( "\n" ); document.write( "I have tried this so many different ways. Where am I making my error?
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Algebra.Com's Answer #335730 by richard1234(7193)\"\" \"About 
You can put this solution on YOUR website!
You should definitely review how to multiply polynomials before pursuing a calculus course. To multiply out (2+h)^3, use the binomial theorem and expand.\r
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\n" ); document.write( "\n" ); document.write( "This is assuming you want to evaluate where x=2.\r
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\n" ); document.write( "\n" ); document.write( "Or, if you know that the derivative of x^3 is 3x^2, we can easily find the tangent line.\r
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\n" ); document.write( "\n" ); document.write( "Hence we can write the tangent line in point-slope form\r
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