document.write( "Question 50490: What is the domain of the function f(x) = x^(1/2) ?\r
\n" ); document.write( "\n" ); document.write( " a. all real numbers
\n" ); document.write( " b. all real numbers except x = 0
\n" ); document.write( " c. all real numbers except x = 1
\n" ); document.write( " d. all real numbers except x = -1 and x = 1
\n" ); document.write( " e. all non-negative real numbers
\n" ); document.write( " f. none of these
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Algebra.Com's Answer #33568 by tutorcecilia(2152)\"\" \"About 
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f(x) = x^(1/2) \r
\n" ); document.write( "\n" ); document.write( " f(x) = \"%28sqrt%28x%29%29\"
\n" ); document.write( "You can only find the square root of a number that is greater than or equal to zero. You cannot take the square root of a negative number. Otherwise, it is considered an imaginary number (i).
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\n" ); document.write( "\n" ); document.write( "Since zero is neither negative nor positive, it is considered a \"non-negative\" number. So, x>=0 or x must be equal to or greater than all non-negative real numbers.
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