document.write( "Question 50301This question is from textbook Beginning Algebra
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document.write( ": The length of a rectangle is 2 inches more than twice its width. If the perimeter of the rectangle is 34 inches , find the dimensions of the rectangle.\r
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document.write( "Please help solve.\r
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document.write( "This is what i got. I do not think I did it correctly.\r
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document.write( "2X+2(2X+2)=34 OR 2X+4X+4=34 OR 6X=30 OR X=30/6 OR X=5 \n" );
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Algebra.Com's Answer #33566 by tutorcecilia(2152)![]() ![]() You can put this solution on YOUR website! You are correct!! I came up with the same answer:\r \n" ); document.write( "\n" ); document.write( "P=2(length+width) \n" ); document.write( "34=2[(2w+2)+w] \n" ); document.write( "34=2[(2w+2)+w] \n" ); document.write( "34=2[2w+2+w] \n" ); document.write( "34=2[3w+2] \n" ); document.write( "17=3w+2 \n" ); document.write( "17-2=3w+2-2 \n" ); document.write( "15/3=3w/3 \n" ); document.write( "5=w \n" ); document.write( ". \n" ); document.write( "Check by plugging (w=5) back into the original equation] \n" ); document.write( "34=2[(2(5)+2)+(5)] \n" ); document.write( "34=2[(2(5)+2)+(5)] \n" ); document.write( "34=34 [Checks out] \n" ); document.write( " |