document.write( "Question 494390: Ryan drove his car from A to B at 81 km/hr. His car broke down and he returned by bus at 54 km/hr. His total traveling time was 5 hours. How long was his trip by car? \n" ); document.write( "
| Algebra.Com's Answer #335633 by ptaylor(2198)     You can put this solution on YOUR website! Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r\r \n" ); document.write( "\n" ); document.write( "Let t1= time to travel from A to B \n" ); document.write( "And let t2= time to travel from B to A\r \n" ); document.write( "\n" ); document.write( "Now we are told that t1 + t2=5 and we know that: \n" ); document.write( "t1=d/81 and \n" ); document.write( "t2=d/54 soooooo: \n" ); document.write( "d/81 + d/54 = 5 multiply each term by 162 \n" ); document.write( "2d+3d=810 \n" ); document.write( "5d=810 \n" ); document.write( "d=162 mi \n" ); document.write( "t1=162/81=2 hours---------------------trip by car \n" ); document.write( "and t2=162/54=3 hours--------------------trip by bus\r \n" ); document.write( "\n" ); document.write( "Trip by car + trip by bus=5 hrs \n" ); document.write( "2+3=5 \n" ); document.write( "5=5\r \n" ); document.write( "\n" ); document.write( "Hope this helps---ptaylor \n" ); document.write( " \n" ); document.write( " |