document.write( "Question 482625: What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years? \n" ); document.write( "
Algebra.Com's Answer #335632 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years? \n" ); document.write( "** \n" ); document.write( "Compound interest formula for interest compounded continuously: \n" ); document.write( "A=Pe^rt, r=annual interest rate, P=initial investment, A=amount after t years \n" ); document.write( ".. \n" ); document.write( "900=500e^10r \n" ); document.write( "900/500=e^10r \n" ); document.write( "9/5=e^10r \n" ); document.write( "take log(ln) of both sides \n" ); document.write( "ln(9/5)=10r*lne \n" ); document.write( "log of base=1 \n" ); document.write( "10r=ln(9/5)=.5878 \n" ); document.write( "r=.5878/10=.05878 \n" ); document.write( "ans: \n" ); document.write( "Annual rate of interest compounded continuously = 5.878% \n" ); document.write( " |