document.write( "Question 482625: What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years? \n" ); document.write( "
Algebra.Com's Answer #335632 by lwsshak3(11628)\"\" \"About 
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What rate of interest compounded continuously is needed for an investment of $500 to grow to $900 in 10 years?
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\n" ); document.write( "Compound interest formula for interest compounded continuously:
\n" ); document.write( "A=Pe^rt, r=annual interest rate, P=initial investment, A=amount after t years
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\n" ); document.write( "900=500e^10r
\n" ); document.write( "900/500=e^10r
\n" ); document.write( "9/5=e^10r
\n" ); document.write( "take log(ln) of both sides
\n" ); document.write( "ln(9/5)=10r*lne
\n" ); document.write( "log of base=1
\n" ); document.write( "10r=ln(9/5)=.5878
\n" ); document.write( "r=.5878/10=.05878
\n" ); document.write( "ans:
\n" ); document.write( "Annual rate of interest compounded continuously = 5.878%
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