document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=494358>Question 494358</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Fred begins walking toward's John's house at 3 mi/h. John leaves his house at the same time and walks towards Fred's house on the same path at a rate of 2 mi/h. How long will it be before they meet if the distance between their houses is 4 miles? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335611 by </B><A HREF=/tutors/aboutme.mpl?userid=chessace><B>chessace(471)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=chessace><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=chessace><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Closing at 2+3 M/H, T = D/S = 4/5 hr = 48 mins.<BR>\n" );
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