document.write( "Question 50050: Two algebra classes took the same test. The mean (average) of the first class of twenty students was 90 percent. The average of the second class was 75 percent. If the average grade for the combined classes was 81 percent, how many students were in the second algebra class? \n" ); document.write( "
Algebra.Com's Answer #33561 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Two algebra classes took the same test. The mean (average) of the first class of twenty students was 90 percent.
\n" ); document.write( "HENCE TOTAL MARKS =20*90=1800\r
\n" ); document.write( "\n" ); document.write( " The average of the second class was 75 percent.
\n" ); document.write( "HENCE THEIR TOTAL = 75X...WHERE X IS THEIR STRENGTH.
\n" ); document.write( "If the average grade for the combined classes was 81 percent, \r
\n" ); document.write( "\n" ); document.write( "TOTAL FOR COMBINED CLASS=(X+20)*81=1800+75X
\n" ); document.write( "81X+1620=1800+75X
\n" ); document.write( "81X-75X=1800-1620=180
\n" ); document.write( "6X=180
\n" ); document.write( "X=30=NUMBER OF STUDENTS IN SECOND ALGEBRA CLASS\r
\n" ); document.write( "\n" ); document.write( "how many students were in the second algebra class?
\n" ); document.write( "
\n" );