document.write( "Question 494301: the perimeter of a rectangle is 36. if the lenth is twice the width, find the length, width, and area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #335598 by Maths68(1474)\"\" \"About 
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Given
\n" ); document.write( "Perimeter of rectangle = 36
\n" ); document.write( "Length = Twice the Width
\n" ); document.write( "l=2*w ........(1)
\n" ); document.write( "We know
\n" ); document.write( "Perimeter of rectangle = 2*length + 2*width
\n" ); document.write( "P=2l+2w
\n" ); document.write( "36=2l+2w
\n" ); document.write( "Put the value of l in above equation we have
\n" ); document.write( "36=2(2w)+ 2w
\n" ); document.write( "36=4w+2w
\n" ); document.write( "36=6w
\n" ); document.write( "or we can write
\n" ); document.write( "6w=36
\n" ); document.write( "w=36/6
\n" ); document.write( "w=6
\n" ); document.write( "Put the value of w in (1)
\n" ); document.write( "l=2w ........(1)
\n" ); document.write( "l=2*6
\n" ); document.write( "l=12\r
\n" ); document.write( "\n" ); document.write( "Length is 12 and Width is 6 meters
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