document.write( "Question 494282: how can i solve using substitution?
\n" ); document.write( "x=y+4
\n" ); document.write( "2x+3y=43
\n" ); document.write( "

Algebra.Com's Answer #335592 by stanbon(75887)\"\" \"About 
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how can i solve using substitution?
\n" ); document.write( "x=y+4
\n" ); document.write( "2x+3y=43
\n" ); document.write( "-----
\n" ); document.write( "Solve for \"x\" and solve for \"y\":
\n" ); document.write( "2(y+4) + 3y = 43
\n" ); document.write( "2y+8 + 3y = 43
\n" ); document.write( "5y = 35
\n" ); document.write( "y = 7
\n" ); document.write( "==========
\n" ); document.write( "solve for \"x\":
\n" ); document.write( "x = y+4
\n" ); document.write( "x = 7+4
\n" ); document.write( "x = 11
\n" ); document.write( "-------------
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );