Algebra.Com's Answer #335532 by lwsshak3(11628)![\"\"](\"/images/stars/stars-13.gif\")   You can put this solution on YOUR website! Hi. I'm trying to do my algebra 2 GT homework and I have no idea how to do it by hand. I know how to plug it into the calculator and get the graph and answer, but I don't remember how to do so by hand. The problem says to \"Graph the function. If a > 0 find the minimum value. If a < 0 find the maximum value. The function is y=3x^2 - 4x - 2 \n" ); document.write( "** \n" ); document.write( "What you have here is a parabola whose standard form of an equation is: \n" ); document.write( "y=a(x-h)^2+k, with (h,k) being the (x,y) coordinates of the vertex. \n" ); document.write( "If a>0, the parabola opens upwards and you have a minimum. \n" ); document.write( "If a<0, the parabola opens downwards and you have a maximum. \n" ); document.write( ".. \n" ); document.write( "For given function: \n" ); document.write( "y=3x^2 - 4x - 2 \n" ); document.write( "Complete the square \n" ); document.write( "y=3(x^2-4x/3+16/36)-2-4/3 \n" ); document.write( "y=3(x-4/6)^2-10/3 \n" ); document.write( "vertex(2/3,-10/3) \n" ); document.write( "ans: \n" ); document.write( "since a=3>0 \n" ); document.write( "minimum value=-10/3 \n" ); document.write( ".. \n" ); document.write( "The graph below will help you to graph the function by hand. In addition to the vertex, you can easily get another point by setting x=0. F(0)=-2, the y-intercept. Also, remember the curve is symmetrical about the axis of symmetry, x=4. \n" ); document.write( ".. \n" ); document.write( " |