document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493983>Question 493983</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the measurements of two complementary angles are in the ratio 2:13.Find the measure of the smaller angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335512 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335512\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the measurements of two complementary angles are in the ratio 2:13.Find the measure of the smaller angle.<BR>\n" );
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document.write( "Let the 2 angles be \"x\" and \"90-x\":<BR>\n" );
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document.write( "x/(90-x) = 2/13<BR>\n" );
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document.write( "13x = 2(90-x)<BR>\n" );
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document.write( "13x = 180-2x<BR>\n" );
document.write( "15x = 180<BR>\n" );
document.write( "x = 12 degrees (The smaller angle)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "stan H.<BR>\n" );
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