document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493927>Question 493927</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Three sticks are arranged to form a right triangle. If the lengths of the three sticks are 0.47 m, 0.62 m and 0.78 m, what are the three angles of the triangle?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335493 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335493\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> That does not form a right triangle. However, we can still find the angles using the law of cosines. For example,\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE (.78)^2 = (.47)^2 + (.62)^2 - (.47)(.62)\cos(\alpha)\">\r<BR>\n" );
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document.write( "where alpha is the angle opposite the .78 m side. Solve for cos(alpha) (you might want a calculator) and take the inverse cosine of both sides. Repeat for the other two sides of the triangle. </SPAN>\n" );
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