document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493893>Question 493893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \" Two angles are complementaryn if the sum of the measures of the angles of 90. if one angle is 10 more than 3 times its complement, find the measures of the ywo angles. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335487 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335487\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Two angles are complementaryn if the sum of the measures of the angles of 90. if one angle is 10 more than 3 times its complement, find the measures of the ywo angles<BR>\n" );
document.write( "**<BR>\n" );
document.write( "let x=angle<BR>\n" );
document.write( "90-x=angle's complement<BR>\n" );
document.write( "..<BR>\n" );
document.write( "x=3(90-x)+10<BR>\n" );
document.write( "x=270-3x+10<BR>\n" );
document.write( "4x=280<BR>\n" );
document.write( "x=70º<BR>\n" );
document.write( "other angle=90-70=20º </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );