document.write( "Question 493834: At the movie theatre, child admission is $6.10 and adult admission is $9.20 . On Thursday, three times as many adult tickets as child tickets were sold, for a total sales of $707.70 . How many child tickets were sold that day? \n" ); document.write( "

Algebra.Com's Answer #335473 by swincher4391(1107) $\"\"$ $\"About$

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Let a be the number of adult tickets sold. Similarly, let c be the number of child tickets sold. Ultimately, we will have a system of equations since there are two unknowns.\r
\n" ); document.write( "\n" ); document.write( "We know the total sales were 707.70:
\n" ); document.write( "6.10c + 9.20a = 707.70 \r
\n" ); document.write( "\n" ); document.write( "We also know that a = 3c since there were 3 times as many adult tickets as children tickets. This is all we need.\r
\n" ); document.write( "\n" ); document.write( "Substitute a=3c into the first equation.\r
\n" ); document.write( "\n" ); document.write( "6.10c + 9.20(3c) = 707.70\r
\n" ); document.write( "\n" ); document.write( "6.10c + 27.60c = 707.70\r
\n" ); document.write( "\n" ); document.write( "33.70c = 707.70\r
\n" ); document.write( "\n" ); document.write( "c = 21 <---- Answer\r
\n" ); document.write( "\n" ); document.write( "Extra:\r
\n" ); document.write( "\n" ); document.write( "Now let's say that they wanted to know how many adult tickets were sold.\r
\n" ); document.write( "\n" ); document.write( "We would plug in c =21 into a =3c to find that 63 adult tickets were sold. \r
\n" ); document.write( "\n" ); document.write( "Hope this helped!\r
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