document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493736>Question 493736</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A circle has a radius of 7ft. find the central angle in degrees for a sector with area of 50ft^2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335437 by </B><A HREF=/tutors/aboutme.mpl?userid=MRperkins><B>MRperkins(300)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MRperkins><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MRperkins><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335437\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> first the area of the whole circle is 49pi ft^2<BR>\n" );
document.write( "a portion of that circle is 50 ft^2<BR>\n" );
document.write( "the whole circle is (360/360)*49pi<BR>\n" );
document.write( "so if we let the numerator equal x, set that expression equal to 50 and then solve for x, it will give us the measure of the central angle that we are looking for.<BR>\n" );
document.write( "So, <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%2F360%2A49pi=50 ALIGN=MIDDLE  ALT=\"x%2F360%2A49pi=50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x=18000%2F%2849pi%29 ALIGN=MIDDLE  ALT=\"x=18000%2F%2849pi%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x is about <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=116.93 ALIGN=MIDDLE  ALT=\"116.93\"   DISABLED_style= \"max-width:90%; height:auto;\" > degrees<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );