document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493700>Question 493700</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The word problem is: Steve is six years older than Sarah is now. In ten years he will be twice her age. Find their ages. \r<BR>\n" );
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document.write( "I figured s= steve's age now, and x=sarah's age now. so s+10=Steve in 10 years. and 2x+10=Sarah in 10 years. This is where i start to get confused. <BR>\n" );
document.write( "s+10=2(x+10). so does that make 6+x+10=2(x+10)? If thats true then when i finisht the math why do i get x=-4 or -x=4. can you help please? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335429 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The word problem is: Steve is six years older than Sarah is now. In ten years he will be twice her age. Find their ages. <BR>\n" );
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document.write( "Equations:<BR>\n" );
document.write( "t = s+6<BR>\n" );
document.write( "(t+10) = 2(s+10)<BR>\n" );
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document.write( "Substitute for \"t\" and solve for \"s\":<BR>\n" );
document.write( "(s+6+10) = 2s+20<BR>\n" );
document.write( "s + 16 =  2s+20<BR>\n" );
document.write( "s = -4 yrs old (Sarah will not be born till 4 years pass)<BR>\n" );
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document.write( "t = s+6 = -4+6 = 2 (Steve is 2 years old now<BR>\n" );
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document.write( "Some problems just don't make sense.<BR>\n" );
document.write( "This is one of them.<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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