document.write( "Question 493471: I cannot figure this one out. Can you please help me?
\n" ); document.write( "there was 48 nickles, dimes, and quarters whose value was $8.25. If there were twice as many quarters as dimes, how many coins of each kind were there?
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Algebra.Com's Answer #335355 by stanbon(75887)\"\" \"About 
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there was 48 nickles, dimes, and quarters whose value was $8.25. If there were twice as many quarters as dimes, how many coins of each kind were there?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: n + d + q = 48 coins
\n" ); document.write( "Quantity:: q = 2d
\n" ); document.write( "Value::: 5n + 10d + 25q = 825 cents
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\n" ); document.write( "Substitute for \"q\":
\n" ); document.write( "n + d + 2d = 48
\n" ); document.write( "5n + 10d + 25(2d) = 825
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\n" ); document.write( "Simplify:
\n" ); document.write( "n + 3d = 48
\n" ); document.write( "5n+60d = 825
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\n" ); document.write( "Multiply thru the 1st equation by 5
\n" ); document.write( "5n + 15d = 240
\n" ); document.write( "5n + 60d = 825
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\n" ); document.write( "Subtract and solve for \"d\":
\n" ); document.write( "45d = 585
\n" ); document.write( "d = 13 (# of dimes)
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\n" ); document.write( "q = 2d = 26 (# of quarters)
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\n" ); document.write( "n + 3d = 48
\n" ); document.write( "n + 39 = 48
\n" ); document.write( "n = 9 (# of nickels)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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