document.write( "Question 493471: I cannot figure this one out. Can you please help me?
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document.write( "there was 48 nickles, dimes, and quarters whose value was $8.25. If there were twice as many quarters as dimes, how many coins of each kind were there? \n" );
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Algebra.Com's Answer #335355 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! there was 48 nickles, dimes, and quarters whose value was $8.25. If there were twice as many quarters as dimes, how many coins of each kind were there? \n" ); document.write( "---- \n" ); document.write( "Equations: \n" ); document.write( "Quantity: n + d + q = 48 coins \n" ); document.write( "Quantity:: q = 2d \n" ); document.write( "Value::: 5n + 10d + 25q = 825 cents \n" ); document.write( "----------------------------------------- \n" ); document.write( "Substitute for \"q\": \n" ); document.write( "n + d + 2d = 48 \n" ); document.write( "5n + 10d + 25(2d) = 825 \n" ); document.write( "---- \n" ); document.write( "Simplify: \n" ); document.write( "n + 3d = 48 \n" ); document.write( "5n+60d = 825 \n" ); document.write( "------------------------ \n" ); document.write( "Multiply thru the 1st equation by 5 \n" ); document.write( "5n + 15d = 240 \n" ); document.write( "5n + 60d = 825 \n" ); document.write( "---- \n" ); document.write( "Subtract and solve for \"d\": \n" ); document.write( "45d = 585 \n" ); document.write( "d = 13 (# of dimes) \n" ); document.write( "--- \n" ); document.write( "q = 2d = 26 (# of quarters) \n" ); document.write( "--- \n" ); document.write( "n + 3d = 48 \n" ); document.write( "n + 39 = 48 \n" ); document.write( "n = 9 (# of nickels) \n" ); document.write( "------------------------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |