document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=493259>Question 493259</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you find the measures of two complementary angles?\r<BR>\n" );
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document.write( "m<A= 3x-7<BR>\n" );
document.write( "m<B= 11x-1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335344 by </B><A HREF=/tutors/aboutme.mpl?userid=cleomenius><B>cleomenius(959)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=cleomenius><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=cleomenius><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The two complementary angles will add up to 90 degrees.<BR>\n" );
document.write( "3x - 7 + 11x - 1 = 90 degrees.<BR>\n" );
document.write( "14x = 98<BR>\n" );
document.write( "x = 7<BR>\n" );
document.write( "3(7) - 7 = 14 degrees<BR>\n" );
document.write( "11(7) - 1 = 76 degrees<BR>\n" );
document.write( "14 degrees + 76 degrees = 90 degrees.<BR>\n" );
document.write( "This does check.<BR>\n" );
document.write( "Cleomenius. </SPAN>\n" );
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