document.write( "Question 493168: You inherit $13,000 and you decide to invest the money in two different investments: one paying 10% and the other paying 14%. A year later your investments are worth $14,580. How much did you originally invest in each account? \n" ); document.write( "
Algebra.Com's Answer #335306 by stanbon(75887)\"\" \"About 
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You inherit $13,000 and you decide to invest the money in two different investments: one paying 10% and the other paying 14%. A year later your investments are worth $14,580. How much did you originally invest in each account?
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\n" ); document.write( "Equations:
\n" ); document.write( "Quantity: x + y = 13000
\n" ); document.write( "Interest:0.10x + 0.14y = 1580
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\n" ); document.write( "Multiply thru the Quantity Equation by 10
\n" ); document.write( "Multiply thru the Interest Equation by 100
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\n" ); document.write( "10x + 10y = 130000
\n" ); document.write( "10x + 14y = 158000
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\n" ); document.write( "Subtract and solve for \"y\":
\n" ); document.write( "4y = 28000
\n" ); document.write( "y = $7,000.00 (amt invested at 14%)
\n" ); document.write( "---
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x = 13000-7000 = $6,000.00 (amt. invested at 10%)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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