document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=492998>Question 492998</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with the following word problem:\r<BR>\n" );
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document.write( "Janine bikes 3 mph faster than her sister, Jessica. Janine can ride <BR>\n" );
document.write( "36 miles in 1 hr less time than Jessica can ride the same difference. Find each of their speeds.\r<BR>\n" );
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document.write( "Here's what I have so far:<BR>\n" );
document.write( "36/x - 1 = 36/x-3\r<BR>\n" );
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document.write( "36/x-1x/1x = 36/x-3\r<BR>\n" );
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document.write( "(36-x)(x-3) = (36) (x)\r<BR>\n" );
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document.write( "36x-108-x^2+3x = 36x\r<BR>\n" );
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document.write( "-x^2+3x-108 = 0\r<BR>\n" );
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document.write( "I cannot figure out how to factor the -x^2+3x-108.\r<BR>\n" );
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document.write( "Please help!\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335233 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Janine bikes 3 mph faster than her sister, Jessica. Janine can ride <BR>\n" );
document.write( "36 miles in 1 hr less time than Jessica can ride the same difference. Find each of their speeds. <BR>\n" );
document.write( "Here's what I have so far:<BR>\n" );
document.write( "36/x - 1 = 36/x-3 <BR>\n" );
document.write( "36/x-1x/1x = 36/x-3 <BR>\n" );
document.write( "(36-x)(x-3) = (36) (x) <BR>\n" );
document.write( "36x-108-x^2+3x = 36x <BR>\n" );
document.write( "-x^2+3x-108 = 0 <BR>\n" );
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document.write( "Janine can ride <BR>\n" );
document.write( "36 miles in 1 hr less time than Jessica can ride the same difference (distance). Find each of their speeds. <BR>\n" );
document.write( "x = Jessica's speed<BR>\n" );
document.write( "x+3 is Janine's speed<BR>\n" );
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document.write( "36/(x+3) = (36/x) - 1 = (36-x)/x<BR>\n" );
document.write( "36x = (x+3)*(36-x) = -(x+3)*(x-36)<BR>\n" );
document.write( "-36x = x^2  - 33x - 108<BR>\n" );
document.write( "x^2 + 3x - 108 = 0<BR>\n" );
document.write( "(x+12)*(x-9) = 0<BR>\n" );
document.write( "x = 9\r<BR>\n" );
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