document.write( "Question 492982: (1 pt) What quantity of 65 per cent acid solution must be mixed with a 30 percent solution to produce 630 mL of a 50 per cent solution? \r
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Algebra.Com's Answer #335232 by josmiceli(19441)\"\" \"About 
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Let \"a\" = ml of 65% solution needed
\n" ); document.write( "Let \"b\" = ml of 30% solution needed
\n" ); document.write( "given:
\n" ); document.write( "\"+.65a+\" = acid in 65% solution
\n" ); document.write( "\"+.3b+\" = acid in 30% solution
\n" ); document.write( "(1) \"+a+%2B+b+=+630+\" ml
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\n" ); document.write( "(2) \"+%28+.65a+%2B+.3b+%29+%2F+630+=+.5+\"
\n" ); document.write( "(2) \"+.65a+%2B+.3b+=+.5%2A630+\"
\n" ); document.write( "(2) \"+.65a+%2B+.3b+=+315+\"
\n" ); document.write( "(2) \"+65a+%2B+30b+=+31500+\"
\n" ); document.write( "Multiply both sides of (1) by \"+30+\" and subtract (1) from (2)
\n" ); document.write( "(2) \"+65a+%2B+30b+=+31500+\"
\n" ); document.write( "(1) \"+-30a+-+30b+=+18900+\"
\n" ); document.write( "\"+35a+=+12600+\"
\n" ); document.write( "\"+a+=+360+\"
\n" ); document.write( "and, since
\n" ); document.write( "(1) \"+a+%2B+b+=+630+\"
\n" ); document.write( "(1) \"+360+%2B+b+=+630+\"
\n" ); document.write( "(1) \"++b+=+270+\"
\n" ); document.write( "360 ml of 65% solution are needed
\n" ); document.write( "270 ml of 30% solution are needed
\n" ); document.write( "check answer:
\n" ); document.write( "(2) \"+%28+.65a+%2B+.3b+%29+%2F+630+=+.5+\"
\n" ); document.write( "(2) \"+%28+.65%2A360+%2B+.3%2A270+%29+%2F+630+=+.5+\"
\n" ); document.write( "(2) \"+%28+234+%2B+81+%29+%2F+630+=+.5+\"
\n" ); document.write( "(2) \"+315+%2F+630+=+.5+\"
\n" ); document.write( "(2) \"+315+=+315+\"
\n" ); document.write( "OK
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