document.write( "Question 492733: Doy and his son can do a job in 4 1/2 days, After they have worked for 3 days, Doy got sick and the son finished the task in 6 more days. How many days each required to do the entire task? \n" ); document.write( "
Algebra.Com's Answer #335193 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Doy and his son can do a job in 4 1/2 days, \n" ); document.write( "After they have worked for 3 days, Doy got sick and the son finished the task in 6 more days. \n" ); document.write( " How many days each required to do the entire task? \n" ); document.write( ": \n" ); document.write( "Let d = D's working time alone to do the job \n" ); document.write( "Let s = son's working time to do it \n" ); document.write( "Let the completed job = 1 \n" ); document.write( ": \n" ); document.write( "\"Doy and his son can do a job in 4 1/2 days,\" therefore \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "From the given information, we know that the son worked a total 9 days \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply the 1st equation by 2, use elimination here \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "----------------------------subtraction eliminates s find d \n" ); document.write( " \n" ); document.write( "multiply both sides by d \n" ); document.write( "d = 6 days for D to do the job alone \n" ); document.write( ": \n" ); document.write( "Find s \n" ); document.write( " \n" ); document.write( "multiply by 6s, results: \n" ); document.write( "3s + 6(9) = 6s \n" ); document.write( "54 = 6s - 3s \n" ); document.write( "54 = 3s \n" ); document.write( "s = \n" ); document.write( "s = 18 days for the son to do the job alone \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "We can check these solutions in the 1st equation \n" ); document.write( " \n" ); document.write( ".75 + .25 = 1 \n" ); document.write( " |