document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=492750>Question 492750</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me solve this problem, One side of rectangle is 1 meter less than the length of the diagonal.If the area is 60 meter squared, what are its dimensions? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #335191 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=335191\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> One side of rectangle is 1 meter less than the length of the diagonal. If the area is 60 meter squared, what are its dimensions?<BR>\n" );
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document.write( "Let L = the length of the rectangle<BR>\n" );
document.write( "Let W = the width of the rectangle<BR>\n" );
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document.write( "I says,\"the area is 60 meter squared,\", therefore:<BR>\n" );
document.write( "L * W = 60<BR>\n" );
document.write( "then<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%2FW ALIGN=MIDDLE  ALT=\"60%2FW\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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document.write( "\"One side of rectangle is 1 meter less than the length of the diagonal\"<BR>\n" );
document.write( "Diagonal = W + 1<BR>\n" );
document.write( "Using pythag:<BR>\n" );
document.write( "W + 1 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28L%5E2+%2B+W%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28L%5E2+%2B+W%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Replace L with 60/W<BR>\n" );
document.write( "W + 1 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%28%2860%2FW%29%5E2%2B+W%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%28%2860%2FW%29%5E2%2B+W%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Square both sides<BR>\n" );
document.write( "(W+1)^2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2860%2FW%29%5E2 ALIGN=MIDDLE  ALT=\"%2860%2FW%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > + W^2<BR>\n" );
document.write( "FOIL<BR>\n" );
document.write( "W^2 + 2W + 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3600%2FW%5E2 ALIGN=MIDDLE  ALT=\"3600%2FW%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > + W^2<BR>\n" );
document.write( "W^2 - W^2 + 2W + 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3600%2FW%5E2 ALIGN=MIDDLE  ALT=\"3600%2FW%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "2W + 2 = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3600%2FW%5E2 ALIGN=MIDDLE  ALT=\"3600%2FW%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Multiply both sides by W^2<BR>\n" );
document.write( "2W^3 + 2W^2 = 3600<BR>\n" );
document.write( "2W^3 + 2W^2 - 3600 = 0<BR>\n" );
document.write( "simplify, divide by 2<BR>\n" );
document.write( "W^3 + W^2 - 1800 = 0<BR>\n" );
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document.write( "Plot this equation on your graphing calc, should look like this:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+15%2C+-1000%2C+2000%2C+x%5E3%2Bx%5E2-1800+%29+ ALIGN=MIDDLE  ALT=\"+graph%28+300%2C+200%2C+-6%2C+15%2C+-1000%2C+2000%2C+x%5E3%2Bx%5E2-1800+%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "you can see W ~ 11.8 meters is the width<BR>\n" );
document.write( "and<BR>\n" );
document.write( "L = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=60%2F11.8 ALIGN=MIDDLE  ALT=\"60%2F11.8\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "L ~ 5.1 meters is the length <BR>\n" );
document.write( ";<BR>\n" );
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document.write( "See if that checks out by finding the diagonal<BR>\n" );
document.write( "d = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=sqrt%2811.8%5E2+%2B+5.1%5E2%29 ALIGN=MIDDLE  ALT=\"sqrt%2811.8%5E2+%2B+5.1%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "d = 12.85 which is about 1 inch longer than the width<BR>\n" );
document.write( " </SPAN>\n" );
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