document.write( "Question 50437: Find a vector normal to the surface z + 2xy = x^2 + y^2 at the point (1,1,0).
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document.write( "Normally I would use gradient g(x,y,z)=0 or f(x,y)= x^2 -2xy + y^2 -z but I can't make it work??? \n" );
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Algebra.Com's Answer #33519 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! Find a vector normal to the surface z + 2xy = x^2 + y^2 at the point...P SAY.. (1,1,0). \n" ); document.write( "Normally I would use gradient g(x,y,z)=0 or f(x,y)= x^2 -2xy + y^2 -z but I can't make it work??? \n" ); document.write( "LET US USE SAME METHOD SUGGESTED BY YOU.. \n" ); document.write( "F=X^2+Y^2-2XY-Z=0... \n" ); document.write( "GRAD(F)=i(DF/DX)+j(DF/DY)+k(DF/DZ)....WHERE THE DERIVATIVES ARE ALL PARTIAL DERIVATIVES.HOPE YOU KNOW IT...THIS MEANS WE KEEP ALL VARIABLES EXCEPT ONE UNDER CONSIDERATION CONSTANT .WE FIND THEM ALL AT THE GIVEN POINT P SAY X=1,Y=1,Z=0 \n" ); document.write( "DF/DX=2X-2Y..=2-2=0 \n" ); document.write( "DF/DY=2Y-2X...=0 \n" ); document.write( "DF/DZ=-1...=-1 \n" ); document.write( "HENCE NORMAL TO THE PLANE IS \n" ); document.write( "N=GRAD(F)= -k \n" ); document.write( " |