document.write( "Question 492747: These problems have me stumped, any help would be greatly appreciated!\r
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document.write( "1. solve for x: (x-3)/2 - 3|2x-1|=-5/3\r
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document.write( "2. solve for x: log(base 3)(x+3)-log(base3)(x-1)=2 \n" );
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Algebra.Com's Answer #335177 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 1. solve for x: (x-3)/2 - 3|2x-1|=-5/3 \n" ); document.write( "---- \n" ); document.write( "|2x-1| = 2x-1 if x >= 1/2 \n" ); document.write( "|2x-1| is 1-2x if x < 1/2 \n" ); document.write( "----- \n" ); document.write( "Consider x< 1/2 to get: \n" ); document.write( "(x-3)/2 -3(1-2x) = -5/3 \n" ); document.write( "x-3 - 6(1-2x) = -10/3 \n" ); document.write( "x-3-6+12x = -10/3 \n" ); document.write( "13x = -10/3+9 = 17/3 \n" ); document.write( "x = 17/39 \n" ); document.write( "But 17/39 is not less than 1/2 so no solution in the interval x < 1/2 \n" ); document.write( "------------------------ \n" ); document.write( "Consider x >= 1/2 \n" ); document.write( "(x-3)/2 - 3(2x-1) = -5/3 \n" ); document.write( "--- \n" ); document.write( "Multiply thru by 6: \n" ); document.write( "3(x-3) - 18(2x-1) = -10 \n" ); document.write( "3x-9 -36x+18 = -10 \n" ); document.write( "-33x = -19 \n" ); document.write( "x = 19/33 which is > 1/2 \n" ); document.write( "--- \n" ); document.write( "That is the solution. \n" ); document.write( "=============================== \n" ); document.write( " \n" ); document.write( "2. solve for x: log(base 3)(x+3)-log(base3)(x-1)=2 \n" ); document.write( "--- \n" ); document.write( "log3[x+3)/(x-1)] = 2 \n" ); document.write( "--- \n" ); document.write( "(x+3)/(x-1) = 9 \n" ); document.write( "--- \n" ); document.write( "x+3 = 9x-9 \n" ); document.write( "8x = 12 \n" ); document.write( "x = 3/2 \n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |