document.write( "Question 492720: two automobiles set out simultaneously from places 100 miles apart. they traveled toward each other and passed at the end of 1 hour and 40 minutes. the speed of one automobile was 5 miles per hour greater than of the other. find the speed of each. can you please answer it for me? thanks! \n" ); document.write( "
Algebra.Com's Answer #335164 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Distance they meet from one car = x\r
\n" ); document.write( "\n" ); document.write( "other car travels 100-x miles when they meet.\r
\n" ); document.write( "\n" ); document.write( "distance/time = speed
\n" ); document.write( "1 h 40 mins = 1 2/3 hours = 5/3 hours\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x/(5/3) -(100-x)/(5/3)= 5\r
\n" ); document.write( "\n" ); document.write( "3x/5 - 3(100-x)/5 =5
\n" ); document.write( "(3x-300+3x)/5 = 5\r
\n" ); document.write( "\n" ); document.write( "6x-300=25
\n" ); document.write( "6x= 325
\n" ); document.write( "x=54.16\r
\n" ); document.write( "\n" ); document.write( "one car travels 54.16 miles in 5/3 hours
\n" ); document.write( "so in 1 hour it travels 54.16/(5/3)
\n" ); document.write( "= 32.5 mph
\n" ); document.write( "second car travels 100-54.16 = 45.84 mile
\n" ); document.write( "speed = 45.84/(5/3)= 27.5 mph\r
\n" ); document.write( "\n" ); document.write( "cheers
\n" ); document.write( " \n" ); document.write( "
\n" );