document.write( "Question 492691: a man drove from his home to the airport at a distance of 40 miles and then returned home on the same way. the round trip took 2 hours. his speed on the return trip was 30 miles/hr faster than his speed in going. what was his rate of speed on the trip from his home. \n" ); document.write( "

Algebra.Com's Answer #335152 by mananth(16946) $\"\"$ $\"About$

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Time to airport + time to home = 2hours\r
\n" ); document.write( "\n" ); document.write( "d=40\r
\n" ); document.write( "\n" ); document.write( "going speed=x
\n" ); document.write( "returning speed= x+30 \r
\n" ); document.write( "\n" ); document.write( " $\"%2840%2Fx%29%2B%2840%2F%28x%2B30%29%29=+2\"$ \r
\n" ); document.write( "\n" ); document.write( "Multiply by the LCD x(x+30)\r
\n" ); document.write( "\n" ); document.write( "40(x+30)+40x= 2x(x+30)\r
\n" ); document.write( "\n" ); document.write( "40x+1200+40x=2x^2+60x\r
\n" ); document.write( "\n" ); document.write( "2x^2-80x+60x-1200=0
\n" ); document.write( "2x^2-20x-1200=0
\n" ); document.write( "/2
\n" ); document.write( "x^2-10x-600=0
\n" ); document.write( "(x-30)(x+20)=0
\n" ); document.write( "x= 30 the speed while going to airport\r
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